2l+2w=48
l=2w
2(2w)+2w=48
4w+2w=48
6w=48
w=8
l=2*8=16
So, the length is 16 meters and the width (or breadth) is 8 meters.
Area is length times width, perimeter is twice the sum of length and breadth.
12 meters
2l+2w=24 l=2w 2(2w)+2w=24 4w+2w=24 6w=24 w=4 l=2w=2*4=8 Length is 8 meters, the width (or breadth) is 4 meters.
Let the breadth of the rectangular field be ( b ) meters. Then, the length is ( 2b ) meters. The area is given by the formula ( \text{Area} = \text{length} \times \text{breadth} ), so we have ( 2b \times b = 14450 ). This simplifies to ( 2b^2 = 14450 ), leading to ( b^2 = 7225 ) and ( b = 85 ) meters. Thus, the length is ( 170 ) meters, and the perimeter is ( 2(\text{length} + \text{breadth}) = 2(170 + 85) = 510 ) meters.
The shape boundary that is twice the sum of its length and breadth describes a rectangle. Specifically, if you denote the length as ( L ) and the breadth as ( B ), the formula for the perimeter ( P ) of a rectangle is given by ( P = 2(L + B) ). Therefore, a boundary that is twice the sum of its length and breadth would be represented as ( 2(L + B) ). This indicates that the boundary encompasses the entire perimeter of the rectangle.
Area is length times width, perimeter is twice the sum of length and breadth.
12 meters
2l+2w=24 l=2w 2(2w)+2w=24 4w+2w=24 6w=24 w=4 l=2w=2*4=8 Length is 8 meters, the width (or breadth) is 4 meters.
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
Well, isn't that just a happy little problem to solve! To find the area of a rectangle, you multiply the length by the breadth. And to find the length, you can use the formula: length = (perimeter - 2 * breadth) / 2. Just remember, there are no mistakes, only happy accidents in math!
The shape boundary that is twice the sum of its length and breadth describes a rectangle. Specifically, if you denote the length as ( L ) and the breadth as ( B ), the formula for the perimeter ( P ) of a rectangle is given by ( P = 2(L + B) ). Therefore, a boundary that is twice the sum of its length and breadth would be represented as ( 2(L + B) ). This indicates that the boundary encompasses the entire perimeter of the rectangle.
Perimeter of a rectangle = twice (length + width), in this case 22 m.
The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.
Let the breadth = xSo, length = 2x+1Thus perimeter will be,2(2x+1+x)=122= 6x+2=122So, 6x=122-2=120So, x= 120/6=20Therefore length=2x+1=2(20)+1=41
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
Given: 2w + 2l = 34 l = w + 2 Then: 2w + 2(w + 2) = 34 4w = 30 w = 7.5 l = 9.5
Designate the width by w. Then, from the problem statement, the length = 6 + 2w. The perimeter is twice the width plus twice the length, or: 2w + 2(2w + 6) = 36; or 2w + 4w + 12 = 36; or 6w = 24 or w = 4 meters; the length is 14 meters.