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Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.
The probability is extremely close to 0. The person who is 85 now would be 121 or more in 2050. Of the 7 billion people in the world today, a lot fewer than 700000 will live to 121. And that is a probability of less than 0.0001.
Assuming the returns are nomally distributed, the probability is 0.1575.
19.4%CALCULATION:The probability of at least 2 people having the same birthday in a group of 13people is equal to one minus the probability of non of the 13 people having thesame birthday.Now, lets estimate the probability of non of the 13 people having the same birthday.(We will not consider 'leap year' for simplicity, plus it's effect on result is minimum)1. We select the 1st person. Good!.2. We select the 2nd person. The probability that he doesn't share the samebirthday with the 1st person is: 364/365.3. We select the 3rd person. The probability that he doesn't share the samebirthday with 1st and 2nd persons given that the 1st and 2nd don't share the samebirthday is: 363/365.4. And so forth until we select the 13th person. The probability that he doesn'tshare birthday with the previous 12 persons given that they also don't sharebirthdays among them is: 353/365.5. Then the probability that non of the 13 people share birthdays is:P(non of 13 share bd) = (364/365)(363/365)(362/365)∙∙∙(354/365)(353/365)P(non of 13 share bd) ≈ 0.805589724...Finally, the probability that at least 2 people share a birthday in a group of 13people is ≈ 1 - 0.80558... ≈ 0.194 ≈ 19.4%The above expression can be generalized to give the probability of at least x =2people sharing a birthday in a group of n people as:P(x≥2,n) = 1 - (1/365)n [365!/(365-n)!]
Certain.
74 %
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This is an example of a probability event, specifically a natural disaster event. The likelihood of an earthquake happening in a particular area within a given time frame is a statistical probability based on historical data and geographic factors.
Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.Given the question was asked in 2012, the next time 2012's calendar will be repeated exactly, given that it is a leap year, is not until 2040.
The probability is extremely close to 0. The person who is 85 now would be 121 or more in 2050. Of the 7 billion people in the world today, a lot fewer than 700000 will live to 121. And that is a probability of less than 0.0001.
You are guaranteed to have Sundays in a leap year, so in probability terms that is 1.
The probability is 1 because it happens every year.
Contrary to the above answer, statistics do not work that way. A 100-year flood has a 1% chance of occurring in any given year. That does not mean that there is a 100% chance in a century, just as tossing a coin twice does not guarantee that you will get heads. The probability of a 100 year flood can be found with the following formula: P=1- (0.99)^n P is the probability expressed as a decimal. Multiply this by 100 to get a percentage. n is the number of years. In this case the chance of a 100 year flood occurring in any 100 year period is about .63 or 63%.
Assuming the returns are nomally distributed, the probability is 0.1575.
Probability has been around since the beginning of time.
It is impossible to predict what the next hurricane will be for any location or if a location will be hit in any given year.