Wiki User
∙ 12y ago19.4%
CALCULATION:
The probability of at least 2 people having the same birthday in a group of 13
people is equal to one minus the probability of non of the 13 people having the
same birthday.
Now, lets estimate the probability of non of the 13 people having the same birthday.
(We will not consider 'leap year' for simplicity, plus it's effect on result is minimum)
1. We select the 1st person. Good!.
2. We select the 2nd person. The probability that he doesn't share the same
birthday with the 1st person is: 364/365.
3. We select the 3rd person. The probability that he doesn't share the same
birthday with 1st and 2nd persons given that the 1st and 2nd don't share the same
birthday is: 363/365.
4. And so forth until we select the 13th person. The probability that he doesn't
share birthday with the previous 12 persons given that they also don't share
birthdays among them is: 353/365.
5. Then the probability that non of the 13 people share birthdays is:
P(non of 13 share bd) = (364/365)(363/365)(362/365)∙∙∙(354/365)(353/365)
P(non of 13 share bd) ≈ 0.805589724...
Finally, the probability that at least 2 people share a birthday in a group of 13
people is ≈ 1 - 0.80558... ≈ 0.194 ≈ 19.4%
The above expression can be generalized to give the probability of at least x =2
people sharing a birthday in a group of n people as:
P(x≥2,n) = 1 - (1/365)n [365!/(365-n)!]
Wiki User
∙ 12y agoIt is 1 - 365Cn/365n. This is greater than 0.5 for n greater than or equal to 23.
10^%
367
In probability theory, the birthday problem, or birthday paradox[1] pertains to the probability that in a set of randomly chosen people some pair of them will have the same birthday. In a group of 10 randomly chosen people, there is an 11.7% chance. In a group of at least 23 randomly chosen people, there is more than 50% probability that some pair of them will both have been born on the same day. For 57 or more people, the probability is more than 99%, and it reaches 100% when the number of people reaches 367 (there are a maximum of 366 possible birthdays). The mathematics behind this problem leads to a well-known cryptographic attack called the birthday attack. See Wikipedia for more: http://en.wikipedia.org/wiki/Birthday_paradox
For the chance to be at least 50% that two people share the same birthday, there needs to be 22 people. For the chance to be exactly 100% that two people share the same birthday, there needs to be 366 people. If there was 365 people, there would be a very small chance that each person in the room would have different birthdays. With 366 people, there are not enough individual days for every person to have a different birthday, so there has to be at least one pair.
It is 1 - 365Cn/365n. This is greater than 0.5 for n greater than or equal to 23.
The probability of at least 2 people sharing a birthday in a group of 12 is approximately 0.891. This is calculated using the complement rule, finding the probability that no one shares a birthday and subtracting it from 1. The result indicates that it is highly likely for at least 2 people to share a birthday in a group of 12.
10^%
1-365/[(365-6)*365^6] = 1 Is this O.K ?
December 25th is considered the least popular birthday, as many people avoid scheduling births on holidays like Christmas.
On the manor, the people with the least power were the serfs.
A person shares their birthday with at least nine million different people around the world.
At least 100 all over the world.
367
poor people
d.transients
my wife