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19.4%

CALCULATION:

The probability of at least 2 people having the same birthday in a group of 13

people is equal to one minus the probability of non of the 13 people having the

same birthday.

Now, lets estimate the probability of non of the 13 people having the same birthday.

(We will not consider 'leap year' for simplicity, plus it's effect on result is minimum)

1. We select the 1st person. Good!.

2. We select the 2nd person. The probability that he doesn't share the same

birthday with the 1st person is: 364/365.

3. We select the 3rd person. The probability that he doesn't share the same

birthday with 1st and 2nd persons given that the 1st and 2nd don't share the same

birthday is: 363/365.

4. And so forth until we select the 13th person. The probability that he doesn't

share birthday with the previous 12 persons given that they also don't share

birthdays among them is: 353/365.

5. Then the probability that non of the 13 people share birthdays is:

P(non of 13 share bd) = (364/365)(363/365)(362/365)∙∙∙(354/365)(353/365)

P(non of 13 share bd) ≈ 0.805589724...

Finally, the probability that at least 2 people share a birthday in a group of 13

people is ≈ 1 - 0.80558... ≈ 0.194 ≈ 19.4%

The above expression can be generalized to give the probability of at least x =2

people sharing a birthday in a group of n people as:

P(x≥2,n) = 1 - (1/365)n [365!/(365-n)!]

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Q: What is the probabililty of at least 2 people same birthday from a group of 13 people?
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