When having the number 23 timing it by the letter U and subtracting it by T would be 23. This is a math problem.
5m-t/7
28 t2 - 17 t - 3 = (7t + 1) x (4t - 3)
ur answer is t= -23 -23 x 3= -69 + 46 = -23
The quotient of 6 and t is 6 over t, or 6 divided by t, depending on what t is. ( 6/t )
When having the number 23 timing it by the letter U and subtracting it by T would be 23. This is a math problem.
5m-t/7
28 t2 - 17 t - 3 = (7t + 1) x (4t - 3)
(t + 1)(2t - 3)
ur answer is t= -23 -23 x 3= -69 + 46 = -23
The quotient of 6 and t is 6 over t, or 6 divided by t, depending on what t is. ( 6/t )
To evaluate t-7 over w for t equals -3 and w equals -2, we substitute -3 for t and -2 for w in the expression. This gives us (-3) - 7 over (-2), which simplifies to -10 over -2. Further simplifying, we get 5 as the final result.
(t - 3)(t^2 + 3t + 9)
(t + 3)(t - 15)Ask yourself, what factors of - 45 add up to - 12 ?t = - 3t = 15
t/5
The quotient of T times 12. You will have to find the value of the letter T.
(18v^9 t^10 -30v^7 t^8 +18v^3 t^4)/6v^3 t