Where the side of the equilateral triangle is s and the radius of the inscribed circle is r:
s = 2r * tan 30° = 48.50 cm
3 times 14cm = a perimeter of 42cm
Area is 98cm2
The radius is: 6.267 cm
Assuming that "it" refers to diameter, the radius is 7 cm and the circumference is 44.0 cm.
The area of a triangle is (base)x(height)x1/2.So, we put in your values (base=19, height=14) and we get 19x14x1/2=19x7=133.The area of a triangle with a base of 19cm and a height of 14cm is 133.
3 times 14cm = a perimeter of 42cm
Area is 98cm2
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
The diameter is 28cm
The area of triangle is : 56.0
The radius is: 6.267 cm
Assuming that "it" refers to diameter, the radius is 7 cm and the circumference is 44.0 cm.
There is only one possibility in forming a triangle from the given dimensions and it is 4cm by 14cm by 16cm
The diameter would be 28 cm.
There is no triangle with sides 14 cm, 3cm and 8cm. For a triangle to exist the sum of the two shorter sides must be longer than the remaining side. 3 cm + 8 cm = 11 cm < 14cm
The area of a triangle is (base)x(height)x1/2.So, we put in your values (base=19, height=14) and we get 19x14x1/2=19x7=133.The area of a triangle with a base of 19cm and a height of 14cm is 133.
Circumference = 2*pi*radius or pi*diameter Circumference = 87.9645943 or 88 cm to the nearest cm