The radius is: 6.267 cm
Assuming that "it" refers to diameter, the radius is 7 cm and the circumference is 44.0 cm.
C=2 pi R
A cone with a base radius of 9.9 cm and a height of 14 cm has a volume of 1,436.9 cm3
14(22/7+2) =2(22+2) =44+4 =48
The diameter is 28cm
The radius is: 6.267 cm
The diameter would be 28 cm.
Assuming that "it" refers to diameter, the radius is 7 cm and the circumference is 44.0 cm.
Area of circle = πr2 Exact area = π(14)2 = 196π cm2
C=2 pi R
The circumference of a circle with a diameter of 14cm is: 43.98 cm
A cone with a base radius of 9.9 cm and a height of 14 cm has a volume of 1,436.9 cm3
14(22/7+2) =2(22+2) =44+4 =48
Where the side of the equilateral triangle is s and the radius of the inscribed circle is r:s = 2r * tan 30° = 48.50 cm
Circumference is (pi x diameter of circle). (Diameter is the distance across the circle, going through the very centre. It is also twice the radius, which is the distance from the middle of the circle to the outer edge). In the question you don't indicate what the 14cm is (i.e. diameter/radius ?), so I can't work it out for you.
If what is 14cm? The diameter? The circumference?d = diameter, r = radius, C = circumference, A = area, pi = approx. 3.14If d = 14cm, then r = 7cm.A = (pi)r2 = (pi)(7)2 = (3.14)(49) = 153.86 = about 154cm2.If C = 14cm, use the formula C = 2(pi)r:14 = 2(pi)rr = 14/(2pi) = 14/6.28 = about 2.229 = about 2.23cm.Then A = (pi)r2 = (3.14)(2.229)2 = 3.14(4.970) = about 15.6 cm2.