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Assuming the question was to find a such that Prob(-a < z < a) = 0.6600, the answer is a = 0.954
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It is the Standard normal variable.
It is 0.5
It is the Standard Normal distribution.
If a variable X, is distributed Normally with mean m and standard deviation s thenZ = (X - m)/s has a standard normal distribution.
Yes, to approximately standard normal.If the random variable X is approximately normal with mean m and standard deviation s, then(X - m)/sis approximately standard normal.
It is the Standard normal variable.
a = ±2.12, depending on the inequality for Z.
It is 0.5
It is the Standard Normal distribution.
None.z-scores are linear transformations that are used to convert an "ordinary" Normal variable - with mean, m, and standard deviation, s, to a normal variable with mean = 0 and st dev = 1 : the Standard Normal distribution.
If a variable X, is distributed Normally with mean m and standard deviation s thenZ = (X - m)/s has a standard normal distribution.
An ordinary variable is standardised by taking a linear transformation of it such that the new variable has standard properties. For example, if X is a Gaussian (Normal) variable with mean mu and standard deviation sigma, then Z = (X - mu)/sigma has a Normal distribution with mean 0 and SD = 1: it has been standardised.
The question does not specify what z is but this answer will assume that it is the value of a random variable with a Standard Normal distribution. That being the case, the area under the curve between those values is 0.4875.
0.636 approx.
It is 0.1587
Yes, to approximately standard normal.If the random variable X is approximately normal with mean m and standard deviation s, then(X - m)/sis approximately standard normal.
0.4846