The two page numbers are 64 and 65. 64 x 65 = 4160.
If one of the pages is numbered p, the other is p+1. So p*(p+1) = 420 That is, p2 + p - 420 = 0 which factorises as (p - 20)*(p + 21) = 0 That implies that p = 20 or p = -21. Assuming that pages do not have negative numbers, p = 20 and then the other page is p+1 = 21.
Long Answer: I found it's actually more difficult to draw these 'students standing evenly spaced in a circle' problems with large numbers of students than it is to just develop a rule for the problem using more simplistic circles (such as a circle with four or eight students). Anyway a general rule for these problems is x+(1/2*t)=y, where x is the number of the particular student (1, in this case), t is the total number of students in the circle (must be an even number, otherwise they can't be standing directly opposite) and y will be the number of the student that the student you have picked is facing. Just a note that, obviously, if you picked student number 18 in this case, this would work out to student number 27. All you have to do in this case is subtract 18 from this number. So student number 18 would be facing student number 9. So if y in the above equation is greater than the total number of students, simply subtract the total number of students from the number you get. Short Answer: 1+(1/2*18)= 1+9 = 10 Student 1 will be facing Student 10.
it is on the bottom
750-757
The formula would be: X(X+1)=6162. X^2+X = 6162. X^2+X-6162 = 0; Factor this. (X+79)(X-78)=0. X+79=0 or X=-79; impossible. X-78=0; X=78; first page. Second page X+1=79. Therefore page numbers are 78 & 79. Check: 78*79=6162.
The book is opened to pages 26, on the left, and 27, on the right. The product of 26 times 27 is 702.
Let the two facing pages be represented by x and (x+1). Since the product of the page numbers is 1056, we have the equation x(x+1) = 1056. This simplifies to x^2 + x - 1056 = 0. By solving this quadratic equation, we find the page numbers to be 32 and 33.
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If one of the pages is numbered p, the other is p+1. So p*(p+1) = 420 That is, p2 + p - 420 = 0 which factorises as (p - 20)*(p + 21) = 0 That implies that p = 20 or p = -21. Assuming that pages do not have negative numbers, p = 20 and then the other page is p+1 = 21.
Simple!A x B = 210Think:If 10 x 10 = 100 and 20 x 20 = 400 than the closest is 15 x 15 = 225So, if we used 15 multiplication.Take (225-210= 15)So, the answer is14 x 15 = 210The answer is page 14 and 15. :)Answer provided by Elson Ng
Let the page on the left be ' X '. Then the right-hand page is " X + 1'.Thus x ( x + 1 ) = 2550 = [ X squared ] plus XTry making X = 50.50 x 50 = 2500Then ( 50 x 50 ) + 50 would equal 2550Since this is true, then the pages must be numbered 50 & 51
if we call the first page A and the second page B we know that B = A+1 And if we multiply A by A+1 we get A2 + A. So, we want to find the square root of A... and the only clue we have is that it is close to 272 The square root of 272 = 16.4924. The number of the right hand page of a book is always the odd one. So we can try 16 and 17, and we see instantly that 16 x 17 = 272.
The National Student Loan Data System or NSLDS is a government agency that can help people facing student loan debts. Federal Student Aid can also help.
122 and 123How?|vif the page is double sided then it has two numbers that are added... divide 245 by 2 and you get 122.5 so one page is pg. 122 and the other is pg. 123
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They are 44 and 45.
40 & 41