Q: How when a student opens a mathematics book to two facing pages The product of the page number is 702 find the page numbers?

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Let the page on the left be ' X '. Then the right-hand page is " X + 1'.Thus x ( x + 1 ) = 2550 = [ X squared ] plus XTry making X = 50.50 x 50 = 2500Then ( 50 x 50 ) + 50 would equal 2550Since this is true, then the pages must be numbered 50 & 51

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I guess this is best solved by trial and error. Try to multiply two consecutive numbers; if the product is too low, try higher number, if the product is too high, try lower numbers. For example, 20 x 21 = 420; since this is too low, your numbers are higher than that; 30 x 31 = 930; since this is too high, your numbers are lower than that.I guess this is best solved by trial and error. Try to multiply two consecutive numbers; if the product is too low, try higher number, if the product is too high, try lower numbers. For example, 20 x 21 = 420; since this is too low, your numbers are higher than that; 30 x 31 = 930; since this is too high, your numbers are lower than that.I guess this is best solved by trial and error. Try to multiply two consecutive numbers; if the product is too low, try higher number, if the product is too high, try lower numbers. For example, 20 x 21 = 420; since this is too low, your numbers are higher than that; 30 x 31 = 930; since this is too high, your numbers are lower than that.I guess this is best solved by trial and error. Try to multiply two consecutive numbers; if the product is too low, try higher number, if the product is too high, try lower numbers. For example, 20 x 21 = 420; since this is too low, your numbers are higher than that; 30 x 31 = 930; since this is too high, your numbers are lower than that.

They are page numbers 24 and 25 . ( 24 x 25 = 600 ) The easiest way to solve this is by trial and error. Multiply two consecutive numbers; if the product is too low, try larger numbers, if it is too high, try smaller numbers. You can also write an equation and use the quadratic formula. The equation in this case is x(x+1) = 600. Re-written for use of the quadratic equation, it becomes x2 + x - 600 = 0. This will give you a positive and a negative solution; only the positive solution is sensible in this case.

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The two page numbers are 64 and 65. 64 x 65 = 4160.

Let the two facing pages be represented by x and (x+1). Since the product of the page numbers is 1056, we have the equation x(x+1) = 1056. This simplifies to x^2 + x - 1056 = 0. By solving this quadratic equation, we find the page numbers to be 32 and 33.

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If one of the pages is numbered p, the other is p+1. So p*(p+1) = 420 That is, p2 + p - 420 = 0 which factorises as (p - 20)*(p + 21) = 0 That implies that p = 20 or p = -21. Assuming that pages do not have negative numbers, p = 20 and then the other page is p+1 = 21.

Simple!A x B = 210Think:If 10 x 10 = 100 and 20 x 20 = 400 than the closest is 15 x 15 = 225So, if we used 15 multiplication.Take (225-210= 15)So, the answer is14 x 15 = 210The answer is page 14 and 15. :)Answer provided by Elson Ng

Let the page on the left be ' X '. Then the right-hand page is " X + 1'.Thus x ( x + 1 ) = 2550 = [ X squared ] plus XTry making X = 50.50 x 50 = 2500Then ( 50 x 50 ) + 50 would equal 2550Since this is true, then the pages must be numbered 50 & 51

if we call the first page A and the second page B we know that B = A+1 And if we multiply A by A+1 we get A2 + A. So, we want to find the square root of A... and the only clue we have is that it is close to 272 The square root of 272 = 16.4924. The number of the right hand page of a book is always the odd one. So we can try 16 and 17, and we see instantly that 16 x 17 = 272.

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122 and 123How?|vif the page is double sided then it has two numbers that are added... divide 245 by 2 and you get 122.5 so one page is pg. 122 and the other is pg. 123

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They are 44 and 45.

40 & 41