The greatest integer is 24.
There are none. The only four consecutive integers totaling 90 are 21, 22, 23 and 24.
The integers are 21, 22, 23 and 24.
The numbers are 44 and 46.
Let the four consecutive integers be ( x, x+1, x+2, x+3 ). The sum of these integers can be expressed as ( x + (x + 1) + (x + 2) + (x + 3) = 4x + 6 ). Setting this equal to -354 gives the equation ( 4x + 6 = -354 ). Solving for ( x ), we find ( x = -90 ), so the four consecutive integers are -90, -89, -88, and -87.
let x = integer and x + 2 next consecutive even integer x +(x +2) = 90 2x + 2 = 90 2x + 88 x = 44 and x+2 = 46 44 and 46
There are none. The only four consecutive integers totaling 90 are 21, 22, 23 and 24.
The integers are -92, -91, -90 and -89.
The integers are 21, 22, 23 and 24.
They are: 90+91+92 = 273
Divide the sum of the two consecutive even integers by 2: 90/2 = 45. The smaller of these integers will be one less than 45 and the larger will be one more than 45, so the two consecutive even integers will be 44 and 46.
The numbers are 44 and 46.
90
Let the four consecutive integers be ( x, x+1, x+2, x+3 ). The sum of these integers can be expressed as ( x + (x + 1) + (x + 2) + (x + 3) = 4x + 6 ). Setting this equal to -354 gives the equation ( 4x + 6 = -354 ). Solving for ( x ), we find ( x = -90 ), so the four consecutive integers are -90, -89, -88, and -87.
The sum of all integers between 45 and 90 is 3105.
The integers are 9 and 10.
x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90
There are two consecutive even integers: 90 and 92.