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Q: Two consecutive integers that have a product of 90?

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Divide the sum of the two consecutive even integers by 2: 90/2 = 45. The smaller of these integers will be one less than 45 and the larger will be one more than 45, so the two consecutive even integers will be 44 and 46.

9 and 10

89 and 90.

The integers are -92, -91, -90 and -89.

They are: 90+91+92 = 273

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They are -10 and -9.

They are -10 and -9.

-9 or -10Two consecutive negative integers that can be multiplied together with a product of 90 would be -9 and -10. A number sentence for this equation would be: -9 X -10 = 90.

There are two consecutive even integers: 90 and 92.

Divide the sum of the two consecutive even integers by 2: 90/2 = 45. The smaller of these integers will be one less than 45 and the larger will be one more than 45, so the two consecutive even integers will be 44 and 46.

85, 86 and 87

9 and 10

The numbers are 44 and 46.

89 and 90.

There are none. The only four consecutive integers totaling 90 are 21, 22, 23 and 24.

The greatest integer is 24.

The integers are -92, -91, -90 and -89.