If the numbers are consecutive then the middle number must be one-third of 51. The numbers are thus 16, 17 and 18.
37
The sum is always 3 more than (triple the smallest number).
49 and 51
91 are.
The smallest of the three is 13.
34
Let the three numbers be 'n' , 'n+1', & n+2 ' . (consecutive). Summing n + n+1 + n+ 2 = 48 3n + 3 = 48 Subtract '3' from both sides 3n = 45 Divide both sides by '3'. n = 15 The smallest number. NB THe other two numbers are 15 + 1 = 16 & 15 + 2 = 17
37
The sum is always 3 more than (triple the smallest number).
The smallest is 14.
49 and 51
91 are.
The smallest of the three is 13.
The smallest of the three numbers is 22.
25 (25+27+29=81)
No, it is impossible.
44