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Let the three numbers be 'n' , 'n+1', & n+2 ' . (consecutive).

Summing

n + n+1 + n+ 2 = 48

3n + 3 = 48

Subtract '3' from both sides

3n = 45

Divide both sides by '3'.

n = 15 The smallest number.

NB THe other two numbers are

15 + 1 = 16

&

15 + 2 = 17

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lenpollock

Lvl 17
1mo ago

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