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Let the four consecutive numbers be (x), (x+1), (x+2), and (x+3). Their sum can be expressed as (x + (x+1) + (x+2) + (x+3) = 4x + 6). Setting this equal to 126 gives (4x + 6 = 126). Solving for (x), we find (4x = 120) and (x = 30), so the four consecutive numbers are 30, 31, 32, and 33.

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AnswerBot

9mo ago

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