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Let the numbers be n, n+1, n+ 2, n+3.
Hence
n + n+1 + n+ 2 + n+3 = 35
Collect like terms
4n + 6 = 35
Subtract '6' from both sides
4n = 29
Divide both sides by '4'
n = 7.25 , 8.25, 9.25, 10.25
What else can I help you with?
What are four consecutive integers with a sum of 134?
The numbers are 32, 33, 34 and 35.
What four factors add up to 48 and are between the numbers 30 and 40?
The four factors of 33 add up to 48.
What are 2 consecutive whole numbers that 35 lies between?
Consecutive whole numbers have no other whole numbers between them.
Which two consecutive numbers have a product of 3192?
The numbers are 56 and 57.
How do you find two consecutive numbers that have a product of 1295?
The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.
What are three consecutive numbers that add up to 102?
33, 34 and 35.
What three consecutive numbers add up to 105?
34, 35 and 36.
What are two consecutive number that add up to the number 35?
The numbers are 17 and 18.
What are four consecutive integers with a sum of 134?
The numbers are 32, 33, 34 and 35.
What four factors add up to 48 and are between the numbers 30 and 40?
The four factors of 33 add up to 48.
What tree consecutive number add to 108?
To find three consecutive numbers that add up to 108, let the numbers be represented as ( x - 1 ), ( x ), and ( x + 1 ). The equation is ( (x - 1) + x + (x + 1) = 108 ). Simplifying this gives ( 3x = 108 ), leading to ( x = 36 ). Therefore, the three consecutive numbers are 35, 36, and 37.
What are 2 consecutive whole numbers that 35 lies between?
Consecutive whole numbers have no other whole numbers between them.
What are the numbers when three consecutive odd numbers is 99?
The numbers are 31, 33 and 35.
What two consecutive numbers give the sum of 35?
The numbers are 17 and 18.
What are the 2 consecutive numbers with product of 1190?
Let the number be 'n' & n+1' Hence n(n+1) = 1190 n^(2) + n = 1190 = n^(2) + n - 1190 = 0 It is now in quadratic1^(2) - 4(1)9-1190)]} form . Apply the Quadratic Eq'n. n = { - 1 +/-sqrt[ 1^(2) - 4(1)(-1190)]} / 2(1) n = { -1 sqrt[1 + 4760]} / 2 n = { -1 sqrt[4761]} / 2 n = { -1 +/- 69}/ 2 n = -70/2 = - 35 & n = 68/2 = 34 Hence consecutive numbers are 34, & 35.
Which two consecutive numbers have product of 1190?
34 and 35
What two consecutive odd numbers hve a sum of 68?
The numbers are 33 and 35.
