Let the number be ( x ). The equation can be expressed as ( x + \sqrt{x} = 0 ). Rearranging gives ( \sqrt{x} = -x ). Since the square root of a number is non-negative, the only solution is when ( x = 0 ). Thus, the number is ( 0 ).
When you have calculated the square root of each number, simply add the results together and you will have the answer.
sqrt(n) + 6
Yes, for example: square root of 2, and the negative of the square root of 2.
The number is 81.
225its 256, d square root being 16 which is 3 more dan d sum of d digits !!!
When you have calculated the square root of each number, simply add the results together and you will have the answer.
81
There can't be a prime number that has a square root because the square root would be a factor of the number.
It's not. Take 49 and 16 for example. The square root of the sum is the square root of 65. The sum of the square roots is 11.
If you have a data set, simply take the square root of the sum of the squares of the data points. Let's say you have three numbers a, b, and c. RSS = SQRT(a2 + b2 + c2).
27
The square root of any positive integer can only be a WHOLE NUMBER or IRRATIONAL, so the square root of 7 is irrational.On the other hand, the sum of a rational and an irrational number is always irrational.
sqrt(n) + 6
5607 + 18 = 5625, a perfect square. The perfect square of a square root is the number you started with.
81
Yes, for example: square root of 2, and the negative of the square root of 2.
example for sum of rational numbers is 1/3 + 1/5 Example for sum of irrationals is Pi + e where e is is base of natural log Another is square root of 2 + square root of 3.