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Let the first number be x, the second number be 3x and the third number be 6x-9:

x+3x+6x-9 = 101

10x = 101+9

10x = 110

x = 11

So the numbers are: 1st = 11, 2nd = 33 and the 3rd = 57

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Q: The sum of the numbers is 101 the second number is 3 times the first and the third is 9 less than twice the second?
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