False.
let the integers be n, n+1 and n+2
3n+3 is there sum and we need this to be even for all integers n.
if n is odd, then 3n is odd ( take n=5 3x5=15 odd)
any odd number +3 is even.
if n is even, then 3n is even and an even number plus and 3 is odd so the answer is false
You could just say or prove it is false with a single counter example.
Take the 3 consecutive integers, 2,3,4 their sum is 9 and you are done.
I mentioned the 3n+3 so you can see why it is false for even set of 3 when the first of the 3 consecutive numbers is even.
Three even integers.Three even integers.Three even integers.Three even integers.
The three integers are 25, 26, and 27.
Any set of three odd integers must be odd - for example, 3 + 5 + 7 = 15. Similarly, the sum of an even number of odd integers added together will always be an even integer.
The integers are -30, -28 and -26.
The integers are -16 and -14.
Three even integers.Three even integers.Three even integers.Three even integers.
The three integers are 25, 26, and 27.
34 & 36
There is no solution. The sum of multiple even integers will always be even, and -7 is odd.
No. There is no set of three consecutive even integers with a sum of 40.
Any set of three odd integers must be odd - for example, 3 + 5 + 7 = 15. Similarly, the sum of an even number of odd integers added together will always be an even integer.
The even integers are 22, 24 and 26.
Find three consecutive positive even integers whose sum is 123 , Answer
The integers are -30, -28 and -26.
The integers are -16 and -14.
The integers are -14, -12 and -10.
16+18+20= 54