It is 42 because 42+43+44 = 129
The numbers are 41, 43 and 45.
There are none.
They are: 41+43+45 = 129
X is the 1st integerX+1 would be the 2ndX+2 would be the 3rdX+(X+1)+(X+2) = 1323X+3=1323X+3-3=132-33X=129X=129/3 = 43So the consecutive integers are 43, 44, 45
Yes if it follows 128
129 divided by 3 is 43, so the 3 consecutive integers having a sum of 129 are 42, 43, and 44.
The numbers are 41, 43 and 45.
There are none.
Suppose the middle number is x. The smallest is x-1, the largest is x+1. So their sum is x-1 + x + x+1 = 3x ie 3x = 384 so that x = 128 So the three integers are 127, 128 and 129.
They are: 41+43+45 = 129
The numbers whose sum is 129 are 41, 43 and 45.
X is the 1st integerX+1 would be the 2ndX+2 would be the 3rdX+(X+1)+(X+2) = 1323X+3=1323X+3-3=132-33X=129X=129/3 = 43So the consecutive integers are 43, 44, 45
They are 128, 129 and 130.
41,43,45 is the answer
Let's represent the three consecutive odd numbers as x, x+2, and x+4. Since odd numbers are always 2 units apart, we can express them this way. Adding these three numbers together, we get x + (x+2) + (x+4) = 129. Combining like terms, we have 3x + 6 = 129. Solving for x, we find x = 41. Therefore, the three consecutive odd numbers are 41, 43, and 45.
43+45+47=135. i had this question for my online math class. but i don't know how to make that into an equation. something like 3x+2...maybe.. here is how you do it: We need three consecutive odd integers so we will let the first one be x, the next is x+2 and then third is x+4 3x+6=135 3x=129 x-43 x+2=45 x+4=47 So the three numbers are 43, 45 and 47
Yes if it follows 128