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43+45+47=135. i had this question for my online math class. but i don't know how to make that into an equation. something like 3x+2...maybe.. here is how you do it: We need three consecutive odd integers so we will let the first one be x, the next is x+2 and then third is x+4 3x+6=135 3x=129 x-43 x+2=45 x+4=47 So the three numbers are 43, 45 and 47
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The sum of three consecutive integers is 135 What is the greatest of the three integers?
Given the sum of three consecutive integers 135, we write out the expression as:x + (x + 1) + (x + 2) = 135 where:x = smallest integerx + 1 = middle integerx + 2 = largest integerSolve for x by rearranging the terms:3x + 3 = 1353x = 132x = 44Therefore, the largest integer is x + 2 = 46.
Three consecutive numbers have a sum of 135?
44,45,46
What are the two consecutive intengers with the sum of 271?
135 and 136.
What is three quarters of 180?
Three quarters of 180 can be calculated by multiplying 180 by 0.75, as 0.75 represents three quarters or 75% of the whole. Therefore, three quarters of 180 is 135.
What is three times fifty four?
135.
