n + (n + 1) + (n + 2) = 27
3n + 3 = 27
n = 8
Thus, the numbers are 8, 9, and 10, and the least of these is 8.
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No. Any three consecutive numbers will have at least one of them which is divisible by 2, which means it cannot be prime. And since 1 is not considered a prime number, it cannot happen.
As the number 1 is considered a special case and not a prime, there cannot be three consecutive numbers that are prime. Any three consecutive numbers must include at least one even number. With the exception of the number 2, no even numbers are prime.
The least of the three numbers is 199.
3 consecutive numbers cannot be prime factors. Any three consecutive numbers would include at least one even number. The only even prime number is 2, and (2,3,4) doesn't qualify.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.