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The sum of three numbers is 62 the largest is six less than three times the smallest and the middle is four less than twice the smallest find the three numbers?
a+b+c = 62. a=3c-6. b=2c-4. a = 62 - b - c.
3a = 186 - 3b - 3c.
3a = 192 - 3b - 3c - 6.
3a = 192 - 3b - a.
2a = 192 - 3b.
2a = 192 - 6c - 12.
2a = 180 - 6c.
2a = 180 - 6(a/3 + 2).
2a = 180 - 2a + 12.
4a = 192.
a = 48.
48 = 3c - 6
54 = 3c
18 = c
a + b + c =62
48 + b + 18 = 62
b=-4
(a=48, b=-4, 18=c) b=2c-4 is not true so i think either some of that tower of math is wrong or you typed in the problem wrong or no solution, likelyhood in that order.
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