Q: The sum of two consecutive even integers is 58what is the larger integer?

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Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.

No.A positive integer is always larger than a negative integer. In the case of two negative integers, the integer with the larger absolute value is actually smaller.

no one wants to know the answer. its freaking math

There are no whole negative numbers greater than -1. Therefore, -1 is the highest negative whole integer. It can be thought of this way: When positive integers get larger, an amount is greater, but when negative integers get larger, the amount is less, so -1 is the greatest negative integer.

Suppose n is the smaller integer. Then the larger integer is n + 1, so that 5 times the larger is 5*(n + 1). Their sum is n + 5*(n + 1) = 6n + 5 Therefore 6n + 5 = 41 6n = 41 - 5 = 36 So that n = 36/6 = 6

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the sum of two consecutive integers is -241, what is the larger integer?

5

x+3 and x+4 would be consecutive integers.

-1

There can be no such integers: a smaller integer cannot be 5 times the larger number.

One possible answer is -4 and -3.

116 + 118 = 234. Answer is 118. Took 5 seconds to do.

114.As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:Where x is the smaller number,x + (x + 2) = 2262x + 2 = 2262x = 224x = 112Therefore the larger integer is 112 + 2 = 114

3*(x+1) - x = 7 So 3x + 3 - x = 7 then 2x = 4 or x = 2 So the two integers are 2 and 3

There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.

Let the smaller integer be x, then then larger integer is x + 2, and: 3x + (x + 2) = 58 → 4x = 56 → x = 14 → The two integers are 14 and 16.

Let x = 1st integer, since consecutive even integer differs by 2 then the 2nd integer = x + 2. So we have, x + 4(x + 2) = 48 x + 4x + 8 = 48 5x = 40 x = 8 (1st integer) Thus, the integers are 8 and 10. Check.