Let n be the smaller of the two odd numbers.
n + (n+2) = 44
Solving, we get n = 21.
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Let's call the first odd number x. Since the numbers are consecutive, the second odd number would be x + 2. The sum of the two numbers is 44, so the equation would be x + (x + 2) = 44. Solving this equation yields x = 21, which means the two consecutive odd numbers are 21 and 23.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
There are none.
All odd numbers are the sum of two consecutive numbers. Odd multiples of 7 less than 25 are 7 and 21.
There are no two consecutive numbers that equal 70 because the sum of any two consecutive numbers is an odd number.
33 & 35.