Q: The sum of two consecutive positive integers is less than 50?

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The 3 consecutive odd positive integers are 7, 9 and 11.

The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1

There are 44 positive integers less than 2,010 that have an odd number of factors.

The product is 30.

That's a list of five consecutive real, rational, natural, positive integers, that are greater than any number less than 40, and less than any number greater than 44 .

Related questions

The 3 consecutive odd positive integers are 7, 9 and 11.

The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1

All of them from 45 to 99 ... 55 integers.

The integers are 5 and 7.

The answer is, obviously, 9.

The sum of such numbers is 504.

The set of positive odd integers.

Two consecutive integers will be 0.5 more and 0.5 less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is -3471.5, so the two consecutive integers are -3472 and -3471.

The sum of the first positive odd integers less than 101 is 10,000.

The pair of consecutive integers which add up to 55 are 27 and 28. Therefore, any consecutive pair of numbers below 27 and 28 add up to a total less than 55.

Positive integers are greater than zero. Negative integers are less than zero.

There are no positive integers less than any negative ones.