1.05
1200 dimes multiplied by 10 cents per dime gives the monetary value of the coins in cents--12,000 cents. Dividing this by 25 cents, the value of a single quarter, gives the number of quarters, or 480.
Yes, but only a few cents above face value.
The value of 5 quarters is 125 cents. Whether that is in dimes or whatever else, the value is always 125 cents. If, for some unknown and perverse reason, you want to use 5 quarters to buy nickels, then you'll get 5 nickels for each quarter, 25 nickels for all 5 quarters.
25Q + P = 300, Q + P = 60Subtract: 24Q = 240 ==> Q = 10, and then P = 50 Check: 10 quarters = $2.50, + 50 cents = $3.00
1 quarter = 25 x (1) cents 2 quarters = 25 x (2) cents 3 quarters = 25 x (3) cents 4 quarters = 25 x (4) cents . . . 'q' quarters = 25 x (q) cents
exactly 125 cents
25 cents.
Two quarters = 50 cents.
: Let q represent value of a quarter. : Let d represent value of a dime. : Let x represent number of dimes. : q = 0.25 : d = 0.10 : 6q = xd : 6(0.25) = x(0.10) : 1.50 = x(0.10) : 15 = x :Therefore - 15 dimes are needed for 6 quarters. : ( I'm not sure what you meant in your question because of how you worded it out... )
Of course-- they are worth 25 cents.
1.05
25 cents Canadian
1200 dimes multiplied by 10 cents per dime gives the monetary value of the coins in cents--12,000 cents. Dividing this by 25 cents, the value of a single quarter, gives the number of quarters, or 480.
Work in cents...10D + 25Q = 1405 and D = 100 - QSubstitute: 10(100 - Q) + 25Q = 1405ie 1000 - 10Q + 25Q = 1405ie 15Q = 405so Q = 27, making D = 73
25 cents each.
Yes, but only a few cents above face value.