: Let q represent value of a quarter. : Let d represent value of a dime. : Let x represent number of dimes. : q = 0.25 : d = 0.10 : 6q = xd : 6(0.25) = x(0.10) : 1.50 = x(0.10) : 15 = x :Therefore - 15 dimes are needed for 6 quarters. : ( I'm not sure what you meant in your question because of how you worded it out... )
Work in cents...10D + 25Q = 1405 and D = 100 - QSubstitute: 10(100 - Q) + 25Q = 1405ie 1000 - 10Q + 25Q = 1405ie 15Q = 405so Q = 27, making D = 73
Work in cents...10D + 25Q = 675 and D = Q + 8Substitute: 10(Q + 8) + 25Q = 675ie 10Q + 80 + 25Q = 675ie 35Q = 595so Q = 17, making D = 25
85 dimes = 85*10 cents = 85*10/25 quarters = 34 quarters.
Work in cents...10D + 25Q = 850 and D = 55 - QSubstitute: 10(55 - Q) + 25Q = 850ie 550 - 10Q + 25Q = 850ie 15Q = 300so Q = 20, making D = 35
i think its 4q
exactly 125 cents
25 cents.
Two quarters = 50 cents.
: Let q represent value of a quarter. : Let d represent value of a dime. : Let x represent number of dimes. : q = 0.25 : d = 0.10 : 6q = xd : 6(0.25) = x(0.10) : 1.50 = x(0.10) : 15 = x :Therefore - 15 dimes are needed for 6 quarters. : ( I'm not sure what you meant in your question because of how you worded it out... )
Of course-- they are worth 25 cents.
1.05
25 cents Canadian
1200 dimes multiplied by 10 cents per dime gives the monetary value of the coins in cents--12,000 cents. Dividing this by 25 cents, the value of a single quarter, gives the number of quarters, or 480.
Work in cents...10D + 25Q = 1405 and D = 100 - QSubstitute: 10(100 - Q) + 25Q = 1405ie 1000 - 10Q + 25Q = 1405ie 15Q = 405so Q = 27, making D = 73
25 cents each.
Yes, but only a few cents above face value.