1 quarter = 25 x (1) cents
2 quarters = 25 x (2) cents
3 quarters = 25 x (3) cents
4 quarters = 25 x (4) cents
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'q' quarters = 25 x (q) cents
: Let q represent value of a quarter. : Let d represent value of a dime. : Let x represent number of dimes. : q = 0.25 : d = 0.10 : 6q = xd : 6(0.25) = x(0.10) : 1.50 = x(0.10) : 15 = x :Therefore - 15 dimes are needed for 6 quarters. : ( I'm not sure what you meant in your question because of how you worded it out... )
Work in cents...10D + 25Q = 1405 and D = 100 - QSubstitute: 10(100 - Q) + 25Q = 1405ie 1000 - 10Q + 25Q = 1405ie 15Q = 405so Q = 27, making D = 73
85 dimes = 85*10 cents = 85*10/25 quarters = 34 quarters.
Work in cents...10D + 25Q = 675 and D = Q + 8Substitute: 10(Q + 8) + 25Q = 675ie 10Q + 80 + 25Q = 675ie 35Q = 595so Q = 17, making D = 25
Work in cents...10D + 25Q = 850 and D = 55 - QSubstitute: 10(55 - Q) + 25Q = 850ie 550 - 10Q + 25Q = 850ie 15Q = 300so Q = 20, making D = 35
i think its 4q
Let ( q ) be the number of quarters and ( d ) be the number of dimes. We have two equations based on the problem: ( q + d = 102 ) (the total number of coins) ( 25q + 10d = 1710 ) (the total value in cents) Solving these equations, we find that there are 6 quarters and 96 dimes.
exactly 125 cents
25 cents.
Two quarters = 50 cents.
: Let q represent value of a quarter. : Let d represent value of a dime. : Let x represent number of dimes. : q = 0.25 : d = 0.10 : 6q = xd : 6(0.25) = x(0.10) : 1.50 = x(0.10) : 15 = x :Therefore - 15 dimes are needed for 6 quarters. : ( I'm not sure what you meant in your question because of how you worded it out... )
25 cents Canadian
Of course-- they are worth 25 cents.
1.05
To find the combinations of nickels, dimes, and quarters that equal 80 cents, we can use the equation (5n + 10d + 25q = 80), where (n), (d), and (q) are the numbers of nickels, dimes, and quarters, respectively. By systematically varying the values of (q) (from 0 to 3, since 3 quarters equal 75 cents) and solving for (n) and (d), we can determine the valid combinations. Through this method, there are 12 valid combinations of nickels, dimes, and quarters that total 80 cents.
1200 dimes multiplied by 10 cents per dime gives the monetary value of the coins in cents--12,000 cents. Dividing this by 25 cents, the value of a single quarter, gives the number of quarters, or 480.
The value of 40 quarters is $10. This is calculated by multiplying the number of quarters (40) by the value of each quarter (25 cents). Therefore, 40 x 0.25 = $10.