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There are 6 brown 5 blue and 2 orange marbles in a hat. What is the probability of picking two orange marbles in a row without returning the marbles back to the hat?
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A bag has 7 blue marbles and 8 purple marbles.What is the probability of picking a blue marble then a purple marble without replacing?
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
What does without replacement mean in probability?
Im not good at explaining things but here's an example. If I have 5 red marbles and 6 blue marbles in a bag and I pick one out. I then choose another marble without returning the first marble to the bag. Hope this helps.
What is the probability of 6 green marbles?
We can't answer that without knowing what else is in the bowl.
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
In a bag there are 3 red marbles and B blue marbles. Two marbles are randomly selected from the bag without replacement. The probability that the two marbles are the same color is 0.5. What is the sum?
7
A bag has 7 blue marbles and 8 purple marbles.What is the probability of picking a blue marble then a purple marble without replacing?
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
What does without replacement mean in probability?
Im not good at explaining things but here's an example. If I have 5 red marbles and 6 blue marbles in a bag and I pick one out. I then choose another marble without returning the first marble to the bag. Hope this helps.
A bag contains 5 green marbles 3 yellow and 2 red marbles. What is the probability of picking three green marbles from the bag without replacement?
To find the answer to probability, first add all the things together (5+3+2=10), then, find the number of things you will be taking from the group of things (3), and put together as a fraction (3/10). So the final answer is 3/10, which is unlikely. :D
What is the probability of 6 green marbles?
We can't answer that without knowing what else is in the bowl.
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
In a bag there are 3 red marbles and B blue marbles. Two marbles are randomly selected from the bag without replacement. The probability that the two marbles are the same color is 0.5. What is the sum?
7
You have 12 marbles 8 are blue 4 are green what is probability one of each color is chosen on the first two draws?
If the two marbles are drawn without replacement, the probability is 16/33.
If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?
4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.
What is the probability that at least one marble is white if a bag has 3 green and 3 white marbles four marbles are selected at the same time?
The probability is 100%.There's no way to take four marbles out of this bag without at least one of them being white.
What is the probability of chossing 12 marbles from a jar in numercial order?
The probability of picking the #1 marble on the first draw is 1/12. If you've done that, then the probability of picking the #2 marble on the second draw is 1/11. If you've done that, then, the probability of picking the #3 marble on the third draw is 1/10. If you've done that, then, the probability of picking the #4 marble on the fourth draw is 1/11. etc. etc. So the probability of doing all of them in sequence is (1/12) x (1/11) x . . . x (1/1). That's exactly the reciprocal of (12!). According to my $1.49 calculator, your chances of success without peeking amount to about 0.00000020877 percent (rounded) Not a smart bet.
A container holds 6 red marbles and 4 green marbles You select 2 marbles from each container without replacement What is the probability that you will select 1 red marble and 1 green marble?
sure chance
How do you find the probability of 4 blue marbles 5 red marbles 1 green marble and 2 black marbles?
It depends what probability exactly you want to find.probability = number of successful ways / total number of waysIf the problem is:You have a bag containing 4 blue, 5 red, 1 green, 2 black marble what is the probability of picking a blue marble at random?Thensuccessful ways = 4 as there are 4 blue marblestotal ways = 12 as there are 4 [blue] marbles + 5 [red] marbles + 1 [green] marble + 2 [black] marbles = 12 marbles in total.pr(picking a blue) = 4/12 = 1/3Perhaps the problem is:You pick 2 marbles at random without replacing them, what is the probability that they are the two black marbles?Each picking of a marble is an event and the two events are independent (in the sense that whatever you pick first does not affect the probability of the second pick) so you multiply the probability of each together:pr(1st black) = 2/12 = 1/6pr(2nd black) = 1/11 (there is 1 less black marble in the bag)pr(2 blacks) = 1/6 × 1/11 = 1/66Perhaps it is:You pick 2 marbles at random replacing the marble after the first pick, what is the probability of picking the same colour each time?This time there are 4 possible colours and the probabilities of 2 marbles the same is calculated for each (similar to above) and then they are added together to find the total probability of 2 marbles of the same colour:pr(blue) = 4/12 → pr(2 blue) = 4/12 × 4/12 = 16/144pr(red) = 5/12 → pr(2 red) = 5/12 × 5/12 = 25/144pr(green) = 1/12 → pr(2 green) = 1/12 × 1/12 = 1/144pr(black) = 2/12 → pr(2 black) = 2/12 × 2/12 = 4/144→ pr(2 the same colour) = pr(2 blue) + pr(2 red) + pr(2 green) + pr(2 black)= 16/144 + 25/144 + 1/144 + 4/144 = 46/144 = 23/72And so on.
