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4/8 or 1/2(probability of first draw) * 3/8(probability of second draw

which is 12/64 or 3/16 of the given scenario.

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What is the probability of not drawing a green marble?

To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.


A bag has 13 green marbles What is the probability pf drawing out a green marble?

your probability would be 13/13. you would have a 100 percent chance of getting a green marble


A bag contains 16 red marbles and 10 blue marbles If two marbles are chosen at random what is the probability of getting two red marbles?

The probability is 0.3692


What is the probability drawing a blue marble from a bag of 18 marblesin a bag three of which are blue?

The probability of drawing a blue marble from a bag containing 18 marbles, of which 3 are blue, is calculated by dividing the number of blue marbles by the total number of marbles. Therefore, the probability is ( \frac{3}{18} ), which simplifies to ( \frac{1}{6} ). Thus, the probability of drawing a blue marble is approximately 0.167 or 16.7%.


What is the probability you will select 2 red marbles if you have 3 red marbles and 1 green marble in a bag You draw 1 marble and without putting it back you draw a 2nd one?

To find the probability of selecting 2 red marbles without replacement, first consider the total number of marbles, which is 4 (3 red and 1 green). The probability of drawing the first red marble is ( \frac{3}{4} ). After drawing the first red marble, there are now 2 red marbles left out of 3 total marbles, making the probability of drawing a second red marble ( \frac{2}{3} ). Therefore, the combined probability of both events is ( \frac{3}{4} \times \frac{2}{3} = \frac{1}{2} ) or 50%.

Related Questions

If a box contains 4 red marbles seven white and 5 blue and two marbles are drawn one at a time with replacement What is the probability that both marbles are white?

Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.


What is the probability of not drawing a green marble?

To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.


What is the theoretical probability of randomly drawing a green marble if there are 5 red marbles 8 blue marbles and 12 green marbles in a bag.?

The theoretical probability of randomly drawing a green marble can be calculated by dividing the number of green marbles by the total number of marbles in the bag. In this case, there are 12 green marbles out of a total of 5 red marbles + 8 blue marbles + 12 green marbles, which is 25 marbles in total. Therefore, the theoretical probability of drawing a green marble is 12/25 or 48%.


There are 9 red and 6 blue marbles in a jar If you draw red marbles from the jar 7 times what is the experimental probability of drawing a red marble?

The answer is dependent on whether of not you replace the marbles in the jar. If you do, the probability of drawing a red marble is 9 in 15 or 60%, every time. If you do not replace the marbles, the probability of drawing a red marble is 2 in 8 or 25%.


A bag has 13 green marbles What is the probability pf drawing out a green marble?

your probability would be 13/13. you would have a 100 percent chance of getting a green marble


A bag contains 3 blue marbles 7 red marbles and 5 yellow marbles. If Joe picks 1 marble from the bag at random what is the probability that it will be blue?

A bag of marbles contains 13 marbles. 5 Blue, 3 Yellow, 4 Green and 1 Red. Leave all answers as a ratio in lowest terms. 18 points On a single draw, what is the probability of drawing a yellow marble? What is the probability of not drawing a yellow marble? What are the odds in favor of drawing a blue marble? What is the probability of drawing a red or yellow marble? What is the probability of drawing a purple marble? If you had to bet on drawing a marble of a certain color what color would you not choose?


A bag contains 16 red marbles and 10 blue marbles If two marbles are chosen at random what is the probability of getting two red marbles?

The probability is 0.3692


What is the probability drawing a blue marble from a bag of 18 marblesin a bag three of which are blue?

The probability of drawing a blue marble from a bag containing 18 marbles, of which 3 are blue, is calculated by dividing the number of blue marbles by the total number of marbles. Therefore, the probability is ( \frac{3}{18} ), which simplifies to ( \frac{1}{6} ). Thus, the probability of drawing a blue marble is approximately 0.167 or 16.7%.


What is the probability you will select 2 red marbles if you have 3 red marbles and 1 green marble in a bag You draw 1 marble and without putting it back you draw a 2nd one?

To find the probability of selecting 2 red marbles without replacement, first consider the total number of marbles, which is 4 (3 red and 1 green). The probability of drawing the first red marble is ( \frac{3}{4} ). After drawing the first red marble, there are now 2 red marbles left out of 3 total marbles, making the probability of drawing a second red marble ( \frac{2}{3} ). Therefore, the combined probability of both events is ( \frac{3}{4} \times \frac{2}{3} = \frac{1}{2} ) or 50%.


A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?

Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4


What is the probability of drawing a marble that is not white?

It depends on how many marbles of each colour you have....


A bag contains 3 blue marbles and 4 red marbles. What is the probability that three randomly drawn marbles without replacement will all be red?

The probability of drawing 3 red marbles in a row from a bag of 3 blue and 4 red marbles without replacement is right at about 0.11 or about 11 in 100, if you want odds.Remember that probability is a pure number between zero (no chance - it's impossible) and 1 (it will happen - it's a certainty). A probability of 0.5 is a 50-50 shot, like a coin toss. We good? Let's move on.We have 7 marbles, and there is a 4 in 7 shot of getting a red marble in the first draw. There is a 3 in 6 shot the next draw since now we only have 6 marbles total (NO replacement) and only 3 red ones (we already drew a red one out). Similarly, there is a 2 in 5 shot of getting a third red one if the first two are red. The probability of the first action (getting a red marble on the first draw) is 4/7 or a probability of about 0.5714. Second draw, it's 3/6 or a probability of 0.5. Last, it's 2/5 or a probability of 0.40. To find the intersection of these probabilities, we just multiply them all together, and we'll get right at about 0.011 for a probability.