(3/4)n + 20 = 65 (multiply by 4 each element in both sides)
3n + 80 = 260 (subtract 80 to both sides)
3n = 180 (divide both sides by 3)
n = 60
Or
(3/4)n + 20 = 65 (subtract 20 to both sides)
(3/4)n = 45 (multiply both sides by 4/3)
n = 60
If a number is increased by 20 and then decreased by 20, the final value remains the same as the original number. This is because the two operations effectively cancel each other out. Therefore, the final value is equal to the original number.
Let the number be ( x ). The equation based on the problem is ( 122 - 5x = x + 20 ). Rearranging gives ( 122 - 20 = 6x ), or ( 102 = 6x ). Dividing both sides by 6, we find ( x = 17 ). Thus, the number is 17.
(108 and 1/3)
To find 20 percent of a number, multiply the number by 0.2. In this instance, 0.2 x 3000 = 600. Therefore, 20 percent of 3000 is equal to 600.
Oh, dude, let me break it down for you. So, if we start with the number x and increase it by 20%, we get 1.20x. And we know that 1.20x is equal to 240. So, to find x, we just divide 240 by 1.20, giving us 200. So, the original number was 200. Easy peasy, like basic math, man.
x+8+x/5 = 20 x = 10
113 + 20 = 133.
47 Impossible problem!
20+2x
20% of 200 is 20/100 * 200 = 40 So 200 increased by 20% is 240.
If a number is increased by 20 and then decreased by 20, the final value remains the same as the original number. This is because the two operations effectively cancel each other out. Therefore, the final value is equal to the original number.
65 - 20 = 4545 = 3/445/3 = 1515 x 4 = 60Another way, if you were required to state it algebraically:.75X + 20 = 65.75X = 45X = 60
Let the number be ( x ). The equation based on the problem is ( 122 - 5x = x + 20 ). Rearranging gives ( 122 - 20 = 6x ), or ( 102 = 6x ). Dividing both sides by 6, we find ( x = 17 ). Thus, the number is 17.
It is 92
(108 and 1/3)
There will be an overall increase in the first number.
Suppose the number is N.Then (N + 4)*2 = N + 20that is, 2N + 8 = N + 20subtracting N from both sides gives: N + 8 = 20subtracting 8 from both sides gives: N = 12.