0
lET THE INTEGERS BE
n < n+2 , N+ 4
Hence their sum is
n + n + 2 + n + 4 = 117
Adding
3n + 6 = 117
Subtract '6' from both sides
3n = 111
Divide both sides by '3'
n = 37
n + 2 = 39
n + 4 = 41
Hence the consecutive odd integers are 37,39, & 41.
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