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lET THE INTEGERS BE

n < n+2 , N+ 4

Hence their sum is

n + n + 2 + n + 4 = 117

Adding

3n + 6 = 117

Subtract '6' from both sides

3n = 111

Divide both sides by '3'

n = 37

n + 2 = 39

n + 4 = 41

Hence the consecutive odd integers are 37,39, & 41.

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lenpollock

Lvl 16
4mo ago

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