123
Well, 47 49 51 53 are four consecutive odd numbers those total squared has for identical digits. 40000.... The square root of any number that is only four digits long all containing the same digit has a value that is not an integer.
12311 ^ 2 = 121; 121 + 2 = 1235^3 = 125; 125 - 2 = 123
There are no three consecutive numbers that are squares. Otherwise, there are an infinite sets of squares of three consecutive numbers: for example, {1,4,9}, or {4,9,16} or {576, 625, 676}
0.00909 has three significant digits.
225its 256, d square root being 16 which is 3 more dan d sum of d digits !!!
Oh, dude, consecutive identical digits are just fancy words for when you have the same number back-to-back. Like when you see 22 or 777 in a row. It's not rocket science, just a fun little pattern that shows up in numbers.
Well, 47 49 51 53 are four consecutive odd numbers those total squared has for identical digits. 40000.... The square root of any number that is only four digits long all containing the same digit has a value that is not an integer.
123 is two less than 53 = 125 and two more than 112 = 121
12311 ^ 2 = 121; 121 + 2 = 1235^3 = 125; 125 - 2 = 123
The only three-digit number that fits the criteria of being a square number and having a product of its digits equal to two is 128. This is because 128 is a square number (11^2 = 121, 12^2 = 144) and the product of its digits (1 x 2 x 8) equals 16, which is not equal to two. Therefore, there is no three-digit number that meets all the given conditions.
There are no three consecutive numbers that are squares. Otherwise, there are an infinite sets of squares of three consecutive numbers: for example, {1,4,9}, or {4,9,16} or {576, 625, 676}
four
0.00909 has three significant digits.
two digits - three and zero
Three significant digits.
102 is the smallest three digit number with different digits.
121 121 = 11^2 1 x 2 x 1 = 2