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Tickets are sold for 3.00 per child and 9.00 per adult they sold a total of 419. tickets for 1905.00 how many of each type of ticket did they sell?
Ok
Let Children=C
Let Adult=A
Set up two equations:
3C+9A=$1905
C+A=419 tickets
Solve the second equation for C or A, I'm choosing A
A=419-C
Sub it into the other equation
3C+9(419-C)=1905
3C+3771-9C=1905 Distribute
3771-6C=1905 Combine like terms
-6C=(-1866) Subtract 3771 from both sides
C=311 Divide by -6
Take 311 and plug it into the other equation "C+A=419"
to find A=108
Answer
Sold 108 adult tickets and 311 child tickets
What else can I help you with?
A charity sells tickets for a fund raising dinner Each adult's ticket costs 10 and each child's ticket costs 5 A total of 1050 was raised by selling 130 tickets How many adult and child tickets?
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Sold 325 tickets to a game Adult tickets were 5 each and student tickets were 2 each How many of each type of ticket were sold is 995 was made?
Let A be the number of adult tickets sold. As 325 tickets in total were sold, the number sold to students was 325 - A. The income from the sale of adult tickets = A x 5 = 5A The income from the sale of student tickets = (325 - A) x 2 = 650 - 2A Total Income = 995 = 5A + 650 - 2A = 3A + 650 3A = 995 - 650 = 345 A = 115, therefore S = 325 - 115 = 210. 115 Adult tickets were sold and 210 Student tickets.
Michelle sold tickets for the basketball gameEach adult costs 3.00 and each student ticket cost 1.50 There were 105 tickets sold for a total of 250.00How many of each type of ticket were sold?
Sounds like a system of equations. X = adult ticket Y = student ticket Change all to pennies for convenience. X + Y = 105 300X + 150Y = 25000 -150(X + Y = 105) - 150X - 150Y = - 15750 300X + 150Y = 25000 -----------------------------------add them 150X = 9250 X = 62 adult tickets ------------------------ Y = 43 student tickets -------------------------- Those two prices added together = $250.50 So, we are a little off. I rounded the adult ticket number, but pieces of tickets can not be sold, so check work.
At a local theatre adult tickets cost 8 and student tickets cost 5 at a recent show 500 were sold for a total of 3475 how many adult tickets were sold?
answer is 325 adult tickets were sold ( fmtickets.com )
Sam took his family to the zoo an adults ticket is two times the cost of a child's ticket the total cost for two adults tickets and three childrens tickets was 28 how much do the tickets cost?
I'll try to explain it.We know that an adult's ticket is two times the cost of a child's ticket. We will call the child's ticket "y". If we do so, the adult's ticket will be 2"y" because it's two times the cost of a child's ticket. We also know that the total cost is 28. Now, we'll write an equation, knowing the number of children and adults and the relationship between the costs:2*2y will be the two adult's tickets.3*y will be the three children's tickets.The equation:2*2y+3*y=284y+3y=287y=28y=4Now, we know that ONE child's ticket costs 4. To find out how much an adult's ticket costs, we have to double it (look at the exercise, it says that an adult's ticket is two times the cost of a child's ticket).4*2=8Finally, we've found out that a child's ticket costs 4 and an adult's ticket costs 8.We can check it as well:2*8+3*4=16+12=28
The movie charges 4.00 for each child ticket and 7.00 for each adult ticket the Art Calub purchased a total of 20 tickets and spent 101.00 How many of each type of ticket did the club buy?
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How much money does one ticket at amc lennox town center 24 cost?
If you buy online the adult tickets are $7, the kid tickets are $6, and the senior tickets are $5. If you buy at the theater the adult tickets are $6, the kid tickets are $5, and the senior tickets are $5. So, if you're planning on going to the movies, you should buy your tickets at the theater.
Mimi had 174 to buy tickets to a concert The adult tickets cost 10.50 and the student tickets cost 7.50 She bought 4 more student tickets than adult tickets How many adult tickets did she buy?
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Mimi had 174 to buy tickets to a concert The adult tickets cost 10.50 and the student tickets cost 7.50 She bought 4 more student tickets than adult tickets How many student tickets did she buy?
12 student tickets
A total of 725 tickets were sold for the school play There were 75 more student tickets sold than adult tickets How many adult tickets were sold?
325 Tickets sold to adults 400 tickets sold to students
Sold 325 tickets to a game Adult tickets were 5 each and student tickets were 2 each How many of each type of ticket were sold is 995 was made?
Let A be the number of adult tickets sold. As 325 tickets in total were sold, the number sold to students was 325 - A. The income from the sale of adult tickets = A x 5 = 5A The income from the sale of student tickets = (325 - A) x 2 = 650 - 2A Total Income = 995 = 5A + 650 - 2A = 3A + 650 3A = 995 - 650 = 345 A = 115, therefore S = 325 - 115 = 210. 115 Adult tickets were sold and 210 Student tickets.
Michelle sold tickets for the basketball gameEach adult costs 3.00 and each student ticket cost 1.50 There were 105 tickets sold for a total of 250.00How many of each type of ticket were sold?
Sounds like a system of equations. X = adult ticket Y = student ticket Change all to pennies for convenience. X + Y = 105 300X + 150Y = 25000 -150(X + Y = 105) - 150X - 150Y = - 15750 300X + 150Y = 25000 -----------------------------------add them 150X = 9250 X = 62 adult tickets ------------------------ Y = 43 student tickets -------------------------- Those two prices added together = $250.50 So, we are a little off. I rounded the adult ticket number, but pieces of tickets can not be sold, so check work.
A total of 700 tickets were sold for the school play There were 50 more student tickets sold than adult tickets How many adult tickets were sold?
700/2 = 350350 - 25 = 325325 adult tickets700 - 325 = 375375 kids tickets
A drama club sold 120 child tickets and 80 adult tickets to a play a child ticket is 3 dollars less than an adult ticket The club sold a total of 640 dollars worth of tickets What were the prices?
The tickets are $5 adult and $2 child. Here is the algebraic substitution. A = adult ticket money C = child ticket money 120C + 80A = 640 C = A-3 (three dollars less) 120 (A-3) + 80A = 640 120 A - 360 + 80A = 640 200 A = 1000 A = 5 C = A - 3 = 2 Checking your answer: 120(2) + 80 (5) = 240 + 400 = 640
At a local theatre adult tickets cost 8 and student tickets cost 5 at a recent show 500 were sold for a total of 3475 how many adult tickets were sold?
answer is 325 adult tickets were sold ( fmtickets.com )
