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a line passes through the point (-2,5) and through the point (3,6) write the equation of the line?
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What else can I help you with?
Write in slope intercept form the equation of the line that is parallel to the given line and passes through the given point?
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
What is the equation of a line through the point (2 17) and has a slope of 7?
Point: (2, 17)Slope: 7Equation: y = 2x+13
How do you write the equation of a line that passes through the point 4 and 2 and has a slope of 2?
Y=2x+6
What is used to write a equation of a line with a given slope that passes through a given point?
(0,-6) m=-2
Write the equation of the line that passes through the points 12 and 6 and 12 and -4?
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
A line passes through the point and has a slope of Write an equation for this line?
Y=mx+b
What is an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line?
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
What is the point slope equation for the line that passes through the point 5 and 5?
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
Write in point slope form the equation of a line that has a slope of -3 and passes through point (2 4) use y-y1m(x-x1)?
Point: (2, 4) Slope: -3 Equation: y = -3x+10
Could you write the equation of the line that is perpendicular to the line given that passes through the point shown?
Yes, I could, if I knew the slope of the line given.
How do you write the equation of a line that is parallel to y23x-2 and passes through -47?
To write the equation of a line that is parallel to ( y = 23x - 2 ), you need to use the same slope, which is 23. The point through which the line passes is (-4, 7). You can use the point-slope form of the equation of a line: ( y - y_1 = m(x - x_1) ). Substituting in the slope (23) and the point (-4, 7), the equation becomes ( y - 7 = 23(x + 4) ), which simplifies to ( y = 23x + 99 ).
How does using the point slope form a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
