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∙ 14y agoRate of acceleration = Change in speed/time
= (30 m/s - 10 m/s) / 5 s
= (20 m/s )5 s = 20/5 ms-2 = 4 ms-2
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∙ 14y agoA marble traveling at 3.0m/s starts to acceleration at 4.5m/s over a distance of 25m. what is the final speed of the marble?
If a stone falls from a ledge and takes 16 seconds to hit bottom, then the bottom is 1413 meters away. This assumes acceleration due to gravity of 9.81 meters per second squared, an initial velocity of zero, and no friction due to air resistance. Air resistance will decrease the distance.x = 1/2 at2 + v0t + x0
when it has reached 60 seconds, click on the record bottom at the end a click it.
We can't tell the height; but the distance between the top and the bottom is 578.7 feet. (rounded)
Always read from the bottom of the meniscus (where the liquid reaches up the side of the container).
The speed of the rock when it reaches the bottom of the cliff can be calculated using the formula for free fall: speed = acceleration due to gravity x time. Given the acceleration due to gravity is approximately 9.81 m/s^2 and the time is 9 seconds, the speed of the rock when it reaches the bottom will be approximately 88.29 m/s.
A marble traveling at 3.0m/s starts to acceleration at 4.5m/s over a distance of 25m. what is the final speed of the marble?
The acceleration is greatest at the top and bottom of the motion.
The depth of the mine can be calculated using the formula: distance = 1/2 * acceleration due to gravity * time squared. Given the time is 6 seconds and the acceleration due to gravity is about 9.8 m/s^2, the depth of the mine would be approximately 176.4 meters.
The depth of the mine can be calculated using the formula: distance = 0.5 * acceleration due to gravity * time^2. Given that the time taken for the stone to hit the bottom is 3 seconds, we can substitute this into the formula along with the acceleration due to gravity (9.8 m/s^2) to calculate the depth of the mine. The depth of the mine would be approximately 44.1 meters.
The velocity of a ball rolling down a hill will increase due to the acceleration caused by the pull of gravity. As the ball gains speed, its velocity will continue to increase until it reaches the bottom of the hill.
The duration of The Dollar Bottom is 1980.0 seconds.
The velocity of the rock when it reaches the ground after falling for 2.5 seconds can be found using the kinematic equation: v = gt where: v = final velocity (m/s) g = acceleration due to gravity (9.81 m/s^2) t = time (2.5 seconds) Plugging in the values: v = 9.81 m/s^2 * 2.5 s = 24.525 m/s Therefore, the velocity of the rock as it reaches the ground is approximately 24.525 m/s.
The duration of WWE Bottom Line is 2700.0 seconds.
the top reaches the bottom and sees the light and reflacts
Answer this question… How fast will a sled be moving when it reaches the bottom of a hill?
That's no more true than it is to say that if everybody in an elevator will jump up when the elevator reaches the bottom, there will be no people on the floor of the elevator when it reaches bottom.