Call the first variable x, then the next one will be x+1. Your equation is thus:
x2 + (x+1)2 = 20.
Your next steps would be to open the parentheses for (x+1) squared; add similar terms; and solve the quadratic equation.
2 because 22+42 = 20
Let the two consecutive positive numbers be ( x ) and ( x + 1 ). The equation for the sum of their squares is ( x^2 + (x + 1)^2 = 164 ). Simplifying this gives ( x^2 + x^2 + 2x + 1 = 164 ), or ( 2x^2 + 2x - 163 = 0 ). Solving this quadratic equation, we find ( x = 9 ) and ( x + 1 = 10 ). Thus, the two consecutive positive numbers are 9 and 10.
5
numbers that come after one another (ie 3,4) and that are positive
The sum of the squares of two consecutive positive numbers is 41.What is the smaller number?Improved Answer:-It is 4 because 42+52 = 41
2 because 22+42 = 20
There aren't two positive consecutive numbers that have an LCM of 200.There aren't two positive consecutive numbers that are multiples of 7.Other than that...
Let the two consecutive positive numbers be ( x ) and ( x + 1 ). The equation for the sum of their squares is ( x^2 + (x + 1)^2 = 164 ). Simplifying this gives ( x^2 + x^2 + 2x + 1 = 164 ), or ( 2x^2 + 2x - 163 = 0 ). Solving this quadratic equation, we find ( x = 9 ) and ( x + 1 = 10 ). Thus, the two consecutive positive numbers are 9 and 10.
27*28 = 756
There are none. However, there are two consecutive positive odd numbers: 25 and 27.
Either use trial-and-error (try different numbers), or solve an equation like n + (n+1) = 61.
5
numbers that come after one another (ie 3,4) and that are positive
5
The sum of the squares of two consecutive positive numbers is 41.What is the smaller number?Improved Answer:-It is 4 because 42+52 = 41
Let's denote the three consecutive numbers as x, x+1, and x+2. Since the sum of these three numbers is 150, we can write the equation x + (x+1) + (x+2) = 150. Simplifying this equation gives us 3x + 3 = 150. Solving for x, we get x = 49. Therefore, the three consecutive numbers are 49, 50, and 51.
The numbers are 5 and 6.