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Let the two consecutive positive numbers be ( x ) and ( x + 1 ). The equation for the sum of their squares is ( x^2 + (x + 1)^2 = 164 ). Simplifying this gives ( x^2 + x^2 + 2x + 1 = 164 ), or ( 2x^2 + 2x - 163 = 0 ). Solving this quadratic equation, we find ( x = 9 ) and ( x + 1 = 10 ). Thus, the two consecutive positive numbers are 9 and 10.
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The sum of the squares of two consecutive positive even integers is 340 Find the integers?
12 and 14.
Find two consecutive positive even number such that sum of their squares is 164?
82 + 102 = 64 + 100 = 164
Find two positive consecutive integers whose product is 72?
The numbers are 8 and 9.
What two consecutive numbers whose squares differ by 25?
Let the two consecutive numbers be ( n ) and ( n + 1 ). The difference of their squares can be expressed as ( (n + 1)^2 - n^2 ), which simplifies to ( 2n + 1 ). Setting this equal to 25, we get the equation ( 2n + 1 = 25 ). Solving for ( n ), we find ( n = 12 ), so the two consecutive numbers are 12 and 13.
Find two consecutive numbers with a product of 4160?
Find two consecutive numbers with the value of 4160
What is The sum of the squares of two consecutive positive even integers is 340 Find the integers?
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
The sum of the squares of two consecutive positive even integers is 340 Find the integers?
12 and 14.
Find the two consecutive positive integers is 132 find the integers?
The numbers are 65 and 67.
Find two consecutive positive even number such that sum of their squares is 164?
82 + 102 = 64 + 100 = 164
The product of 2 positive consecutive even integers is 48 What is the smaller number?
The product of 2 consecutive positive number is 48. Find the 2 numbers
Find two consecutive positive numbers such that the sum of their square is 113?
Ans - 7and 8
Find two positive consecutive integers whose product is 72?
The numbers are 8 and 9.
What two consecutive numbers whose squares differ by 25?
Let the two consecutive numbers be ( n ) and ( n + 1 ). The difference of their squares can be expressed as ( (n + 1)^2 - n^2 ), which simplifies to ( 2n + 1 ). Setting this equal to 25, we get the equation ( 2n + 1 = 25 ). Solving for ( n ), we find ( n = 12 ), so the two consecutive numbers are 12 and 13.
Find two consecutive odd numbers such that the sum of their squares is 74?
5 and 7 52+72 = 74
Find two consecutive numbers with a product of 4160?
Find two consecutive numbers with the value of 4160
Two positive numbers differ by 7 and the sum of their squares is 169. Find the number?
169 = 144 + 25, so your numbers are 12 & 5.
The sum of the squares of two consecutive negative odd integers is 74 Find the integers?
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
