3:4 or 75%
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
It depends upon what the parents were. If both parents were dwarf and white, then it is 100% If both parents were heterozygous for both traits, then it is 1/16. If either parent were homozygous tall and colored, then it is 0. Make a Punnett Square to get all of the probabilities if you know the genotypes of the parents.
Genotype is used to determine the probability of having specific offspring from two known parents.
The probability that a child will be heterozygous depends on the parent's genotypes. If one parent is heterozygous (Aa) and the other is also heterozygous (Aa), then there is a 50% chance (1 out of 2 possible genotypes) that their child will be heterozygous. If both parents are homozygous (AA or aa), then all their children will be heterozygous.
3:4 or 75%
It is a 75% chance that the seeds will be round.
If both parents have a dominant widow's peak trait (which is likely a dominant genetic trait), they may still carry the recessive allele for a straight hairline. When they both pass on their recessive allele for straight hairline to their child, the child would exhibit the recessive trait for a straight hairline. This is possible through the inheritance of different alleles for the same trait from each parent.
The probability that a given child will have PKU is 25%. This is because both parents are carriers of the recessive allele (heterozygous), so there is a 25% chance that they will each pass on the recessive allele, resulting in the child having PKU.
It can happen when both parents are a heterozygous
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
If both parents are heterozygous for seed shape (Rr), their offspring would have a 75% chance of producing round seeds (3 out of 4 possible combinations), assuming round seeds (R) are dominant over wrinkled seeds (r).
That depends on the genes of the parents.
Heterozygous means inheriting different genes from your parents. That is a heterozygous trait, not a homozygous one.