3:4 or 75%
To determine the probability of offspring being i barred females, we need information about the genetic makeup of the parents, specifically their genotypes related to the i barred trait. If both parents carry the i barred allele, we can use a Punnett square to analyze the potential combinations. The resulting probability will depend on the specific alleles present in the parents. Generally, if both parents are heterozygous for the i barred trait, the probability of producing i barred females could be calculated based on the ratios established in the Punnett square.
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
To determine the probability of offspring having wrinkled seeds, we need to know the genetic makeup of the parents. If we assume that wrinkled seeds are a recessive trait (represented by "r") and smooth seeds are dominant (represented by "R"), then the probability depends on the genotypes of the parents. For example, if both parents are heterozygous (Rr), there is a 25% chance that the offspring will inherit the wrinkled seed trait (rr). Without specific parental genotypes, we cannot provide an exact probability.
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
3:4 or 75%
It is a 75% chance that the seeds will be round.
Yes, because they can carry the trait from their parents. You would need to look at the grandparents on both sides. If one grandparent on the maternal and one on paternal side had a widows peak then the parents could both be a carrier to the widow peak gene (wW), meaning they could produce a child with a widows peak. However, if both the maternal and or paternal grandparents lack a widows peak then it is impossible for a grandchild to have a widows peak because both parents would be recessive ww (straight hairline). When attempting to figure out genetics it is best to observe three generations for family genetic traits. However, when in doubt you should confirm with a paternity test.
The probability that a given child will have PKU is 25%. This is because both parents are carriers of the recessive allele (heterozygous), so there is a 25% chance that they will each pass on the recessive allele, resulting in the child having PKU.
It can happen when both parents are a heterozygous
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
If both parents are heterozygous for seed shape (Rr), their offspring would have a 75% chance of producing round seeds (3 out of 4 possible combinations), assuming round seeds (R) are dominant over wrinkled seeds (r).
That depends on the genes of the parents.
Heterozygous means inheriting different genes from your parents. That is a heterozygous trait, not a homozygous one.