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Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six
fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
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What are the ratios of a heterozygous dihybrid cross and what is the probability of having the recessive trait show?
9:3:3:1 The probability of having both recessive traits is 1:16.
What is the probability a woman heterozygous for an x-linked trait will have a son with a genetic disorder if the genetic disorder is recessive?
The probability would be 0.5 or 50%. A heterozygous woman will pass on the X chromosome with the recessive allele to 50% of her sons, and since the disorder is recessive, the son would only have the disorder if the X chromosome with the recessive allele is inherited from the mother.
If both heterozygous parents are carriers of a recessive allele for phenylketonuria the probability that a given child of these parents will have PKU is?
The probability that a given child will have PKU is 25%. This is because both parents are carriers of the recessive allele (heterozygous), so there is a 25% chance that they will each pass on the recessive allele, resulting in the child having PKU.
Galactosemia is a recessive human disease A woman and her husband are both heterozygous for the glactosemia gene She has identical twins What is the probability that they are both girls and have ga?
The probability both twins are girls is 0.25 (0.5 * 0.5). Each girl will inherit half of the mother's genes, so there is a 0.25 chance they both inherit the galactosemia gene from their heterozygous mother. Therefore, the probability that they are both girls and have galactosemia is 0.25 * 0.25 = 0.0625 or 6.25%.
In a dihybrid cross with genotypes JjQq and JJQq what is the probability of getting an offspring with genotype?
To determine the probability of getting offspring with a specific genotype from a dihybrid cross between JjQq (heterozygous for both traits) and JJQq (homozygous for J and heterozygous for Q), we can set up a Punnett square. The possible gametes from JjQq are JQ, Jq, jQ, and jq, while the possible gametes from JJQq are JQ and Jq. By combining these gametes, we can calculate the probabilities for each genotype based on their combinations. The specific probability will depend on the genotype in question.
What is a probability of 2 Rh plus heterozygous have 4 Rh- children?
1/8 or 12.5%
What is the probability of 2 heterozygous individuals producing a heterozygous recessive offspring?
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
What is the probability of offspring for 2 heterozygous dogs?
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
What is the probability of a heterhomozygous offspring?
Impossible. You can only be heterozygous or homozygous, not both.
What is the probability of 2 heterozygous individuals producing a homozygous recessive offspring?
25%
If two parents are heterozygous for sickle-cell anemia the probability for each of their children having sickle-cell anemia is?
If both parents are heterozygous for sickle-cell anemia (genotype AS), the probability of each child inheriting the condition (genotype SS) is 25%. This is determined by a Punnett square that shows the possible combinations of alleles from each parent. The genotypes of the children can be AA (normal), AS (carrier), or SS (sickle-cell anemia), with the SS outcome occurring in one out of four possibilities.
What was the probability that two heterozygous parents would have an offspring that produced rounds seeds?
3:4 or 75%
What are the ratios of a heterozygous dihybrid cross and what is the probability of having the recessive trait show?
9:3:3:1 The probability of having both recessive traits is 1:16.
What is probability that two heterozygous parents would have an offspring that produced round seeds?
It is a 75% chance that the seeds will be round.
In humans the allele for brown eyes (B) is dominant to the allele for blue eyes (b). What is the probability that two heterozygous brown-eyed parents will have a child with blue eyes?
If both parents are heterozygous for brown eyes (Bb), the possible allele combinations for their children can be represented in a Punnett square: BB, Bb, Bb, and bb. This means there is a 1 in 4 chance, or a 25% probability, that their child will inherit the blue eye genotype (bb) and therefore have blue eyes.
What is the probability that offspring of a cross between a homozygous recessive parent and a hetezyguous parent will be homozygous recessive?
In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.
Is The probability that a gamete produced by a pea plant heterozygous for stem height Tt will contain the recessive allele 100 percent?
false
