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Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six

fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.

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βˆ™ 13y ago
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βˆ™ 5mo ago

The probability that a child will be heterozygous depends on the parent's genotypes. If one parent is heterozygous (Aa) and the other is also heterozygous (Aa), then there is a 50% chance (1 out of 2 possible genotypes) that their child will be heterozygous. If both parents are homozygous (AA or aa), then all their children will be heterozygous.

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βˆ™ 12y ago

It will depend on the genotype of the parents.

If both parents have the same genotype, say BB - then all of their children should also be BB.

If both parents are heterozygous, Bb - then 50% of their children should also be heterozygous (Bb), 25% BB and 25% bb.

If one parent is BB and the other bb - then all of their children will be heterozygous (Bb).

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βˆ™ 11y ago

If the trait for six fingers is dominant then the odds are 3/4, if the trait is recessive then the odds are 1/4

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βˆ™ 13y ago

50%

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βˆ™ 13y ago

1/2

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Q: What is the probability that the children will be heterozygous?
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Continue Learning about Natural Sciences

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