There is one chance in four of the first card being a diamond (since there are four suits). There is one chance in four of the second card being a diamond. The chances of both being a diamond is 1/4*1/4 = 1/16, or thus one chance in 16
5
It is 0.0039 approx.
In a standard deck of 52 playing cards, there are 13 clubs. The probability of being dealt a club is calculated by dividing the number of clubs by the total number of cards. Thus, the probability is 13/52, which simplifies to 1/4 or 25%.
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.
The probability of drawing two diamonds from a deck of cards is (13 in 52) times (12 in 51), or 156 in 2,652, or 78 in 1,327.
5
The probability of being dealt a blackjack hand with an ace and a nine in a standard deck of cards is 4.83.
There are 13 diamonds. Three cards are dealt. The probability of all of them being diamond is (13/52)(12/51)(11/50) = 1716/132600 = 11/850
hypergeometric distribution: f(k;N,n,m) = f(5;52,13,5)
It is 0.0039 approx.
There are 13 clubs in a standard deck of 52 cards. The probability, then, of drawing club is 13 in 52, or 1 in 4, or 0.25.
The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6
The probability of being dealt a straight with the cards ace, two, three, four, and five in a standard 52-card deck is 0.0000154, or approximately 0.00154.
In a standard deck of 52 playing cards, there are 13 clubs. The probability of being dealt a club is calculated by dividing the number of clubs by the total number of cards. Thus, the probability is 13/52, which simplifies to 1/4 or 25%.
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.
The answer depends on how many cards you are dealt!
The probability of drawing two diamonds from a deck of cards is (13 in 52) times (12 in 51), or 156 in 2,652, or 78 in 1,327.