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∙ 14y agoThere is one chance in four of the first card being a diamond (since there are four suits). There is one chance in four of the second card being a diamond. The chances of both being a diamond is 1/4*1/4 = 1/16, or thus one chance in 16
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∙ 14y ago5
It is 0.0039 approx.
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.
The probability of drawing two diamonds from a deck of cards is (13 in 52) times (12 in 51), or 156 in 2,652, or 78 in 1,327.
The probability that the first four cards are face cards is (16/52)*(15/51)*(14/50)*(13/49) = 43680/6497400 = approx 0.0067
5
There are 13 diamonds. Three cards are dealt. The probability of all of them being diamond is (13/52)(12/51)(11/50) = 1716/132600 = 11/850
hypergeometric distribution: f(k;N,n,m) = f(5;52,13,5)
It is 0.0039 approx.
There are 13 clubs in a standard deck of 52 cards. The probability, then, of drawing club is 13 in 52, or 1 in 4, or 0.25.
The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.
The probability of drawing two diamonds from a deck of cards is (13 in 52) times (12 in 51), or 156 in 2,652, or 78 in 1,327.
The answer depends on how many cards you are dealt!
The probability that the first four cards are face cards is (16/52)*(15/51)*(14/50)*(13/49) = 43680/6497400 = approx 0.0067
If only one card is dealt randomly from a deck of cards, the probability is 1/52.
The probability that five cards chosen at random from a standard deck will all be the same suit is 12/51 * 11/50 * 10/49 * 9/48 = about 0.2%.