P = 1/2 * 1/2 * 1/6 = 1/24
To find the probability of getting an odd number at least once when a die is tossed thrice, we can use the complementary approach. The probability of not getting an odd number (i.e., getting an even number) in a single toss is ( \frac{3}{6} = \frac{1}{2} ). Therefore, the probability of getting an even number in all three tosses is ( \left(\frac{1}{2}\right)^3 = \frac{1}{8} ). Thus, the probability of getting an odd number at least once is ( 1 - \frac{1}{8} = \frac{7}{8} ).
The probability is 50-50.
The probability is 1/4
Coins do not have numbers, there is only the probability of heads or tails.
50%
The probability is 50-50.
It is 0.25
The probability is 1/4
Coins do not have numbers, there is only the probability of heads or tails.
The probability is 3/8 = 0.375
The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5
50%
possible
1/2
50%
It is 0.75
Assuming that it is a fair coin, the probability is 0.9990