Two consecutive numbers with the sum of 103 are 51 and 52.Here's a fun way to figure it out using c++ (can me modified to find any two consecutive numbers adding up to the variable target):
#include
using namespace std;
int main()
{
int target = 103;
int num = 0;
int sum;
while (sum != target)
{
num++;
sum = (num + (num+1));
}
cout << num << "\n" << (num+1);
return 0;
} Or, more simply stated: add one to the target (eg., 103+1=104) and then divide by 2 (104/2=52) This will give the second consecutive number. The first is one less, 51.
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The numbers are 54 and 56.
There are no two consecutive numbers that equal 70 because the sum of any two consecutive numbers is an odd number.
The sum of the numbers is 26. The numbers are 12 and 14.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
There are none.