3 and 10
7 and 6
10 and 3
The factors of 21 are 1, 3, 7, and 21. 3 - 1 = 2
-23
To find two numbers where the difference is 7 and the product is 30, we can set up the equations: ( x - y = 7 ) (difference) and ( x \cdot y = 30 ) (product). Solving these equations, we can express ( x ) as ( y + 7 ) and substitute it into the product equation to find the values of ( x ) and ( y ). The numbers that satisfy both conditions are 10 and 3, since ( 10 - 3 = 7 ) and ( 10 \cdot 3 = 30 ).
The factors of 35 are 1, 5, 7, and 35. There are only two factors with a difference of 2; they are 5 and 7. 1 and 5 have a difference of 4. 1 and 7 have a difference of 6. 1 and 35 have a difference of 34. 5 and 7 have a difference of 2. 5 and 35 have a difference of 30. 7 and 35 have a difference of 28.
7 and 6
7 and 9
7 and 9
10 and 3
The difference of 7 and the product of 30 is calculated by subtracting the product of 30 from 7. The product of 30 is 30 multiplied by 7, which equals 210. Therefore, the difference of 7 and the product of 30 is -203.
12 and 5 10 and 3
30 has 7 factors
The factors of 21 are 1, 3, 7, and 21. 3 - 1 = 2
Factors of 7: 1, 7 Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
-23
To find two numbers where the difference is 7 and the product is 30, we can set up the equations: ( x - y = 7 ) (difference) and ( x \cdot y = 30 ) (product). Solving these equations, we can express ( x ) as ( y + 7 ) and substitute it into the product equation to find the values of ( x ) and ( y ). The numbers that satisfy both conditions are 10 and 3, since ( 10 - 3 = 7 ) and ( 10 \cdot 3 = 30 ).