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It's clear that the first set has 2m subsets and second one has 2n subests.

so we have to solve 2m - 2n = 56 (m,n are positive integers)

Its also clear that m>n

let m = k+n

so 2k+n- 2n= 56

2n(2k- 1)= 23*7

clearly 2k-1 is odd

so 2n= 23, and n = 3

and 2k-1= 7 so k =3

so m = 3+3 = 6 and n = 3

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Q: Two finite sets have m and n elements If A has 56 more subsets than B then what are the values of m and n?
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