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Suppose the one flying West goes at x kph. The other is going at (x + 20) kph.

They get further apart by: x + x + 20 = 2x + 20 kph.

Hence 4*(2x + 20) = 6000

So 2x + 20 = 1500

2x = 1480

x = 740

So the speeds are 740 and 760 kph.

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Q: Two jets leave Ontario at the same time one flying East at a speed of 20 km greater than the other which is flying West. After4 hours the planes are 6000 km apart. Find their speeds?
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