The probability is 11/36. There are 36 possible outcomes, but 25 of these don't involve a 2 on either die.
The way to answer this is to ask what is the probability of not rolling a 2 on either die and subtract this from one.
The probability of not rolling a 2 with the first die is 5/6. It is of course also 5/6 chance of not rolling a 2 with the second die. So we multiply the probabilities and subtract from 1.
1 - (5/6 * 5/6) = 1 - (25/36) = 11/36.
The probability is 1, if the dice are rolled often enough.
Probability is desired options over total options. There are 6 faces on a standard dice, so NOT rolling a 5 is 5/6.
If you're only rolling one die, it's a probability of 1 out of six, or 16.67%.
It is 1/6.
It is 0.9459
The probability is 1, if the dice are rolled often enough.
Probability is desired options over total options. There are 6 faces on a standard dice, so NOT rolling a 5 is 5/6.
If you're only rolling one die, it's a probability of 1 out of six, or 16.67%.
It is 1/6.
1/6
It is 0.9459
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 1, if the dice are rolled often enough.
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
The theoretical probability of rolling a 5 on a standard six sided die is one in six. It does not matter how many times you roll it, however, if you roll it 300 times, the theoretical probability is that you would roll a 5 fifty times.
Well, if you put them back after you take them out, then 3=1/6 7=1/6 and
A standard die has no memory and so the probability of rolling an even number is always a half. If you did not know that the die was standard and were using the fact that 7 out of 12 rolls were even as an empirical estimate for a loaded die then the answer is 7/12.