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Q: Using numbers 1 - 6 can a magic triangle have a sum of 13?

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Sum of numbers in a nth row can be determined using the formula 2^n. For the 100th row, the sum of numbers is found to be 2^100=1.2676506x10^30.

There are 9 numbers. Assuming the question refers to a 3x3 "magic" square, the answer is no. The sum of all nine numbers is 36 so each of the 3 rows must sum to 12.

triangle sum conjecture is the sum of the measures of the angles in every triangle is 180 degrees

By adding 5+1 to get the sum of six.

Pick three numbers. If the square of the largest number is equal to the sum of the squares of the other two, then the three numbers could represent the sides of a right triangle.

Related questions

Sum of numbers in a nth row can be determined using the formula 2^n. For the 100th row, the sum of numbers is found to be 2^100=1.2676506x10^30.

The sum of the numbers on the fifteenth row of Pascal's triangle is 215 = 32768.

1ST one the magic sum is 15 numbers 4 5 and 6

The sum of the numbers in each row of Pascal's triangle is twice the sum of the previous row. Perhaps you can work it out from there. (Basically, you should use powers of 2.)

15, 34 and 42.

1 on top 6 and 2 on the left side of triangle 5 and 3 on right side of triangle 4 at the bottom of triangle The sum should equal 9 on all sides

64

If you simply add numbers the answer is the sum of those numbers.

What is the sum of a triangle?

Any three numbers where the sum of the two smaller numbers is greater than the third number. List the numbers in order from least to greatest, repeating any number if necessary. Add the first two numbers together and if this sum is greater than the third number then a triangle with those sides can be made. ie if the sum of the two smaller numbers is greater than the third number then a triangle can be made.

These numbers added together make the 1000th triangle number, which is 500,500.

It gives you the sum of two or more numbers.

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