Q: V plus f equals e plus 2?

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Topologists, primarily.

13=e+2 11=e (subtract 2 from each side)

(2-r)e-rr

It means that P equaleth zero

'e' is energy. and it is written with a capital 'E'. Hence E = mc^(2). Where 'm' is the mass in 'kilograms'. 'c' is the speed of light NB Note how similar it is to K.E. (kinetric Energy) K.E. = mv^(2). Where 'v' is the veloicty of the object.

Related questions

If e=v+2-r where e = 17, r = 6 then 17 = v + 2 - 6 or v = 21.

Topologists, primarily.

a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19

the answer is a

Zn(s) → Zn2+(aq) + 2e- and Fe3+(aq) + e- → Fe2+(aq)

13=e+2 11=e (subtract 2 from each side)

e times 5 = X

E=mc^2A^2+B^2=C^2E/m=C^2=A^2+B^2E/m=A^2+B^2E=m(A^2+B^2)correct

(2-r)e-rr

It means that P equaleth zero

Energy

In the cell, the half-reaction for silver will be Ag+ (aq) + e- -> Ag (s) with a standard reduction potential of +0.80 V. The half-reaction for copper will be Cu2+ (aq) + 2e- -> Cu (s) with a standard reduction potential of +0.34 V. The silver half-reaction will occur at the cathode, while the copper half-reaction will occur at the anode in the cell.