x2 + 2x - 15 = (x - 3)(x + 5)
The vertex has a minimum value of (-4, -11)
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
(3, -21)
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
x2 + 2x - 15 = (x - 3)(x + 5)
The vertex has a minimum value of (-4, -11)
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
(3, -21)
-2-5
Take the derivative: y' = 2x + 4. Set equal to zero: 2x + 4 = 0 --> x = -2. Substitute into original and y = -3. Axis of symmetry is x = -2. Vertex is (-2,-3)
(2x)ysquared
If you have an equation of x2 plus x2, it is the same as saying 2 times x plus 2 times x. This can be written as 2x + 2x or x2 + x2. It is the same, then, as 4x. For example, if x equals 5: 2(5) + 2(5) = 10 + 10 = 20. 20 also equals 4(5).
The vertex of the positive parabola turns at point (-2, -11)
x = -3y = -14