Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
Since w3 is a multiple of w2, it is automatically the LCM.
I don't know that we're able to predict accurately so far out, but if the heat death of the universe is what actually will happen, then the universe will have been reduced to absolute zero for billions of years by the time we get to 1 googol.
The lateral area L.A. of the right triangular prism is the sum of the areas of its lateral faces, which are rectangles with length the height (l = h = 15) and wide the sides of the triangle (w1 = leg1 = 3, w2 = leg2 = 5, w3 = hypotenuse = 7). So we have: L.A. = (15 x 3) + (15 x 5) + (15 x 7) L.A. = 15(3 + 5 + 7) L.A. = 225 Thus, we can also say that the lateral area of a prism is the product of the perimeter of its base with the height of the prism.
In physics, the center of mass of a system of particles is a specific point at which, for many purposes, the system's mass behaves as if it were concentrated. The center of mass is a function only of the positions and masses of the particles that comprise the system. In the case of a rigid body, the position of its center of mass is fixed in relation to the object (but not necessarily in contact with it). In the case of a loose distribution of masses in free space, such as, say, shot from a shotgun, the position of the center of mass is a point in space among them that may not correspond to the position of any individual mass. In the context of an entirely uniform gravitational field, the center of mass is often called the center of gravity - the point where gravity can be said to act. Center of gravity is the sum (or the integral) of the moments of force from the weight of an object divided by the total weight. COG = [w1*r1 + w2*r2 + w3*r3 + ... + wnrn ] / Σwi (i = 1 to n). COM = [m1*r1 + m2*r2 + m3*r3 + ... + mnrn ] / Σmi (i = 1 to n). In a uniform gravitational field (which is what you usually have), mass is proportional to weight everywhere, so the center of gravity and the center of mass are the same point.
w3+125
w(w - 9)(w + 6)
w3
In order to understand the use of a w3 validator you would need to have at least a Bachelors degree in either Computer language and website building. w3 validators are used to make computer language cleaner between HTML based and XHTML.
112
World Wide Web
Hotspot, 3ixT, and EdgeOne.
Ithishaam/W3$TMANZ---$£%&*S!CKMAD3*&%£$
maibi the whole group iz 13
Help with w3c claim
112
A w3 validator runs side by side with your web browser. It checks and validates that each web documentation you are running and or open are what they say they are and are't going to mess with your computer in harmful manners.